2 4 3
3 In this case, \(N = 2, a = \[ 4, 3 \]\). For the permutation \(p = \[ 1, 2 \]\), a cycle of an only chicken \(1\) and a cycle of an only chicken \(2\) are made, thus \(f(\[1, 2\]) = a_1 \\times a_2 = 12\). For the permutation \(p = \[ 2, 1 \]\), a cycle of two chickens \(1\) and \(2\) is made, and the size of the smallest chicken is \(a_2 = 3\), thus \(f(\[2, 1\]) = a_2 = 3\). Now we know \(b_1 = f(\[2, 1\]) = 3, b_2 = f(\[1, 2\]) = 12\), and the greatest common divisor of \(b_1\) and \(b_2\) is \(3\).
4 2 5 2 5
2 There are always \(N!\) permutations because chickens of the same size can be distinguished from each other. The following picture illustrates the cycles formed and their beauties when \(p = (2, 1, 4, 3)\) and \(p = (3, 4, 1, 2)\), respectively. 
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