4 2 2 5 2 5
12
There are $10$ nonempty contiguous subsequences of $a$. Let us enumerate them:
* contiguous subsequences starting from the first element: ${2}, {2, 5}, {2, 5, 2}, {2, 5, 2, 5}$
* contiguous subsequences starting from the second element: ${5}, {5, 2}, {5, 2, 5}$
* contiguous subsequences starting from the third element: ${2}, {2, 5}$
* contiguous subsequences starting from the fourth element: ${5}$
(Note that even if the elements of subsequences are equal, subsequences that have different starting indices are considered to be different.)
The maximum possible bitwise AND of the beauties of two different contiguous subsequences is $12$. This can be achieved by choosing ${5, 2, 5}$ (with beauty $12$) and ${2, 5, 2, 5}$ (with beauty $14$).8 4 9 1 8 2 7 5 6 4
32
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