3 0.30 0.60 0.80
0.612 The probability of each case where we have more heads than tails is as follows: * The probability of having $(Coin 1, Coin 2, Coin 3) = (Head, Head, Head)$ is $0.3 × 0.6 × 0.8 = 0.144$; * The probability of having $(Coin 1, Coin 2, Coin 3) = (Tail, Head, Head)$ is $0.7 × 0.6 × 0.8 = 0.336$; * The probability of having $(Coin 1, Coin 2, Coin 3) = (Head, Tail, Head)$ is $0.3 × 0.4 × 0.8 = 0.096$; * The probability of having $(Coin 1, Coin 2, Coin 3) = (Head, Head, Tail)$ is $0.3 × 0.6 × 0.2 = 0.036$. Thus, the probability of having more heads than tails is $0.144 + 0.336 + 0.096 + 0.036 = 0.612$.
1 0.50
0.5 Outputs such as `0.500`, `0.500000001` and `0.499999999` are also considered correct.
5 0.42 0.01 0.42 0.99 0.42
0.3821815872
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"statement_type": "Markdown",
"content": "Let $N$ be a positive odd number.\nThere are $N$ coins, numbered $1, 2, \\ldots, N$. For each $i$ ($1 \\leq i \\leq N$), when Coin $i$ is tossed, it comes up heads with probability $p_i$ and tails with pr...",
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