5 1 3 5 4 2
3 3 3 5 3 For example, when $i=2$, if we set $(l,r)=(2,4)$, then $r-l+1=3$ is odd, and the median of $(P_2,P_3,P_4)=(3,5,4)$ is $4$, which is not $P_2$, so the conditions are satisfied. Thus, the answer is $3$. On the other hand, when $i=4$, the median of $(P_l,\dots,P_r)$ for any of $(l,r)=(4,4),(2,4),(3,5)$ is $P_4=4$. If we set $(l,r)=(1,5)$, the median of $(P_1,P_2,P_3,P_4,P_5)=(1,3,5,4,2)$ is $3$, which is not $P_4$, so the conditions are satisfied. Thus, the answer is $5$.
3 2 1 3
\-1 3 3 When $i=1$, no pair of integers $(l,r)$ satisfies the conditions.
14 7 14 6 8 10 2 9 5 4 12 11 3 13 1
5 3 3 7 3 3 3 5 3 3 5 3 3 3
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"content": "You are given a permutation $P=(P_1,P_2,\\dots,P_N)$ of integers from $1$ to $N$.\nFor each $i=1,2,\\dots,N$, print the minimum value of $r-l+1$ for a pair of integers $(l,r)$ that satisfies all of the f...",
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