3 1
Yes
1 2
1 3
2 3
The printed graph has vertex set ${1, 2, 3}$ and edge set ${(1, 2), (1, 3), (2, 3)}$, and is simple. The vertex set $X$ has $6$ non-empty proper subsets: ${1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}$.
* For $X = {1}, {2}, {3}$, the edge sets of the induced subgraphs by $X$ are empty, and the densities are $\displaystyle\frac{0}{1} = 0$.
* For $X = {1, 2}, {1, 3}, {2, 3}$, the edge sets of the induced subgraphs by $X$ are ${(1, 2)}, {(1, 3)}, {(2, 3)}$, respectively, and the densities are all $\displaystyle\frac{1}{2}$.
In all cases, the density of the induced subgraph is strictly less than $D = 1$, so this graph satisfies the condition.4 2
No A simple undirected graph with $4$ vertices and $8$ edges does not exist.
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