4 0 5 1 3 11 2 7 8 1 8 2 2 8 9
2 1 In the second query, $T=\lbrace(0, 5), (3, 11) \rbrace$. For $x=7$, we have $f_T(7)=\min \lbrace \left| \left|7-0\right|-5\right|, \left| \left|7-3\right|-11\right| \rbrace=\min \lbrace 2, 7 \rbrace=2$. Similarly, $f_T(8)=3$. Thus, the answer is $\min \lbrace 2, 3 \rbrace =2$. In the fourth query, $T=\lbrace(0, 5), (3, 11), (8, 2) \rbrace$. In $8 \leq x \leq 9$, $f_T(x)$ takes the minimum value $f_T(9)=1$ at $x=9$.
2 1 2 1 2 3 2 2 6
0
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