To decide which is the strongest among Rock, Paper, and Scissors, we will hold an RPS tournament. There are $2^k$ players in this tournament, numbered $0$ through $2^k-1$. Each player has his/her favorite hand, which he/she will use in every match.
A string $s$ of length $n$ consisting of `R`, `P`, and `S` represents the players' favorite hands. Specifically, the favorite hand of Player $i$ is represented by the $((i\text{ mod } n) + 1)$\-th character of $s$; `R`, `P`, and `S` stand for Rock, Paper, and Scissors, respectively.
For $l$ and $r$ such that $r-l$ is a power of $2$, the winner of the tournament held among Players $l$ through $r-1$ will be determined as follows:
* If $r-l=1$ (that is, there is just one player), the winner is Player $l$.
* If $r-l\geq 2$, let $m=(l+r)/2$, and we hold two tournaments, one among Players $l$ through $m-1$ and the other among Players $m$ through $r-1$. Let $a$ and $b$ be the respective winners of these tournaments. $a$ and $b$ then play a match of rock paper scissors, and the winner of this match - or $a$ if the match is drawn - is the winner of the tournament held among Players $l$ through $r-1$.
Find the favorite hand of the winner of the tournament held among Players $0$ through $2^k-1$.
## Constraints
* $1 \leq n,k \leq 100$
* $s$ is a string of length $n$ consisting of `R`, `P`, and `S`.
## Input
Input is given from Standard Input in the following format:
$n$ $k$
$s$
[samples]
## Notes
* $a\text{ mod } b$ denotes the remainder when $a$ is divided by $b$.
* The outcome of a match of rock paper scissors is determined as follows:
* If both players choose the same hand, the match is drawn;
* `R` beats `S`;
* `P` beats `R`;
* `S` beats `P`.