There are $N$ slimes numbered from $1$ to $N$. The color of each slime is represented by an integer between $0$ and $2K$ (inclusive), and the color of slime $i$ is $C_i$.
Currently, $M$ pairs of slimes are in a (bidirectional) friendship. Specifically, slimes $A_i$ and $B_i$ are friends ($1 \leq i \leq M$). Here, it is guaranteed that for any two slimes, one can reach the other by following friendship relations.
You can perform the following operation:
* First, choose a pair of slimes $(u,v)$ that satisfies both of the following conditions:
* Slimes $u$ and $v$ are in a friendship.
* $(C_u - C_v) \bmod (2K+1) \geq K+1$ (here, the result of $x \bmod y$ is always in the range $[0,y-1]$).
* Then, let slime $u$ eat slime $v$. Slime $v$ disappears from the field. Also, all slimes except $u$ that were in a friendship with slime $v$ become friends with slime $u$ (if they were already friends with slime $u$, nothing happens).
Determine whether it is possible to leave only slime $1$ on the field by repeating the operation appropriately.
Solve $T$ cases for one input.
## Constraints
* $1 \leq T \leq 125000$
* $2 \leq N \leq 250000$
* $N-1 \leq M \leq 250000$
* $1 \leq K \leq N$
* $0 \leq C_i \leq 2K$
* $1 \leq A_i < B_i \leq N$
* $(A_i,B_i) \neq (A_j,B_j)$ ($i \neq j$)
* For any two slimes, one can reach the other by following friendship relations.
* The sum of $N$ over the $T$ cases is at most $250000$.
* The sum of $M$ over the $T$ cases is at most $250000$.
* All input values are integers.
## Input
The input is given from Standard Input in the following format:
$T$
$case_1$
$case_2$
$\vdots$
$case_T$
Each test case is given in the following format:
$N$ $M$ $K$
$C_1$ $C_2$ $\cdots$ $C_N$
$A_1$ $B_1$
$A_2$ $B_2$
$\vdots$
$A_M$ $B_M$
[samples]