Output #1
2
We use a string consisting of `R` and `B`, corresponding to red and blue, to represent the sequence of colors of the chips of a pile from top to bottom. Particularly, the sequence of colors of the chips of a $0$\-chip pile is an empty string $\varepsilon$.
Also, the state where the sequences of colors of chips of the piles on square $1, 2, 3, 4$ are $S_1, S_2, S_3, S_4$, respectively, is called as state $(S_1, S_2, S_3, S_4)$.
The following process yields `RRBB` as the sequence of colors of chips of the pile on square $4$.
* First, on each square, place a chip of the same color as the square, resulting in state $($ `R` $, $ `B` $, $ `R` $, $ `B` $)$.
* Place the pile of chips on square $1$ on top of the pile of chips on square $2$, resulting in state $(\varepsilon, $ `RB` $, $ `R` $, $ `B` $)$.
* Place the pile of chips on square $2$ on top of the pile of chips on square $4$, resulting in state $(\varepsilon, \varepsilon, $ `R` $, $ `RBB` $)$.
* Place the pile of chips on square $3$ on top of the pile of chips on square $4$, resulting in state $(\varepsilon, \varepsilon, \varepsilon, $ `RRBB` $)$.
The following process yields `RBRB` as the sequence of colors of chips of the pile on square $4$.
* First, on each square, place a chip of the same color as the square, resulting in state $($ `R` $, $ `B` $, $ `R` $, $ `B` $)$.
* Place the pile of chips on square $1$ on top of the pile of chips on square $4$, resulting in state $(\varepsilon, $ `B` $, $ `R` $, $ `RB` $)$.
* Place the pile of chips on square $2$ on top of the pile of chips on square $4$, resulting in state $(\varepsilon, \varepsilon, $ `R` $, $ `BRB` $)$.
* Place the pile of chips on square $3$ on top of the pile of chips on square $4$, resulting in state $(\varepsilon, \varepsilon, \varepsilon, $ `RBRB` $)$.
The above two, `RRBB` and `RBRB`, are the only possible sequences of colors of chips of the pile on square $4$ from top to bottom after the process in the problem.