5 3 2 1 2 1 0 1
9 When $i=0$, Takahashi starts at point $0.5$ and moves clockwise. Then, the following happens: * At point $1$, he meets the $1$st, $3$rd, and $5$th people, a total of three people, and the total number of people met so far is $3$. This is not less than $C=2$, so Takahashi stops there. Therefore, $X_0=3$. When $i=1$, Takahashi starts at point $1.5$ and moves clockwise. Then, the following happens: * At point $2$, he meets the $2$nd person. The total number of people met so far is $1$, so he continues moving. * At point $0$, he meets the $4$th person, and the total number of people met so far is $2$. This is not less than $C=2$, so Takahashi stops there. Therefore, $X_1=2$. When $i=2$, Takahashi starts at point $2.5$ and moves clockwise. Then, the following happens: * At point $0$, he meets the $4$th person. The total number of people met so far is $1$, so he continues moving. * At point $1$, he meets the $1$st, $3$rd, and $5$th people, a total of three people, and the total number of people met so far is $4$. This is not less than $C=2$, so Takahashi stops there. Therefore, $X_2=4$. Therefore, the answer is $X_0+X_1+X_2=3+2+4=9$.
1 1000000000000 1 1
1000000000000
Regardless of the starting position, Takahashi stops when he meets the only person standing around the pond, who is at point $1$.
Therefore, $X_i=1$ regardless of $i$, and the answer is $10^{12}$.{
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"content": "There is a pond with a circumference of $M$, and on its shore stand one hut and $N$ people. \nFor a real number $x$ $(0\\leq x <M)$, define point $x$ as the location that is $x$ distance clockwise from...",
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