Output #1
Yes
0 0 0 0 6 0 6 0 0
Consider the case $(a_1, b_1, c_1, a_2, b_2, c_2, a_3, b_3, c_3) = (0, 0, 0, 0, 6, 0, 6, 0, 0)$.

The figure represents the positional relationship of $C_1$, $C_2$, and $C_3$, corresponding to the orange, cyan, and green cubes, respectively.
Here,
* All of $|a_1|, |b_1|, |c_1|, |a_2|, |b_2|, |c_2|, |a_3|, |b_3|, |c_3|$ are not greater than $100$.
* The region contained in all of $C_1, C_2, C_3$ is $(6\leq x\leq 7)\land (6\leq y\leq 7) \land (0\leq z\leq 7)$, with a volume of $(7-6)\times(7-6)\times(7-0)=7$.
* The region contained in exactly two of $C_1, C_2, C_3$ is $((0\leq x < 6)\land (6\leq y\leq 7) \land (0\leq z\leq 7))\lor((6\leq x\leq 7)\land (0\leq y < 6) \land (0\leq z\leq 7))$, with a volume of $(6-0)\times(7-6)\times(7-0)\times 2=84$.
* The region contained in exactly one of $C_1, C_2, C_3$ has a volume of $840$.
Thus, all conditions are satisfied.
$(a_1, b_1, c_1, a_2, b_2, c_2, a_3, b_3, c_3) = (-10, 0, 0, -10, 0, 6, -10, 6, 1)$ also satisfies all conditions and would be a valid output.