Output #1
698771048 698771048 964969543 964969543 133099248
We call a team formed by player $x_1$, player $x_2$, $\ldots$, player $x_k$ as team $\lbrace x_1, x_2, \ldots, x_k \rbrace$.
* The first match is played by team $\lbrace 1 \rbrace$, with player $1$, and team $\lbrace 2 \rbrace$, with player $2$. Team $\lbrace 1 \rbrace$ wins with probability $\frac{1}{2}$, and team $\lbrace 2 \rbrace$ wins with probability $\frac{1}{2}$. Then, the two teams are combined into a single team $\lbrace 1, 2 \rbrace$.
* The second match is played by team $\lbrace 4 \rbrace$, with player $4$, and team $\lbrace 3 \rbrace$, with player $3$. Team $\lbrace 4 \rbrace$ wins with probability $\frac{1}{2}$, and team $\lbrace 3 \rbrace$ wins with probability $\frac{1}{2}$. Then, the two teams are combined into a single team $\lbrace 3, 4 \rbrace$.
* The third match is played by team $\lbrace 5 \rbrace$, with player $5$, and team $\lbrace 3, 4 \rbrace$, with player $3$. Team $\lbrace 5 \rbrace$ wins with probability $\frac{1}{3}$, and team $\lbrace 3, 4 \rbrace$ wins with probability $\frac{2}{3}$. Then, the two teams are combined into a single team $\lbrace 3, 4, 5 \rbrace$.
* The fourth match is played by team $\lbrace 1, 2 \rbrace$, with player $1$, and team $\lbrace 3, 4, 5 \rbrace$, with player $4$. Team $\lbrace 1, 2 \rbrace$ wins with probability $\frac{2}{5}$, and team $\lbrace 3, 4, 5 \rbrace$ wins with probability $\frac{3}{5}$. Then, the two teams are combined into a single team $\lbrace 1, 2, 3, 4, 5 \rbrace$.
The expected numbers of times the teams with players $1, 2, 3, 4, 5$ win throughout the tournament, $E_1, E_2, E_3, E_4, E_5$, are $\frac{9}{10}, \frac{9}{10}, \frac{53}{30}, \frac{53}{30}, \frac{14}{15}$, respectively.