5 4 1 2 3 2
1 3 2 4 For $i = 2$, the operations change $B$ as follows. * Initially, $B = (1,2,3,4,5)$. * Perform the operation for $k=1$. That is, swap the values of $B_1$ and $B_2$, making $B = (2,1,3,4,5)$. * Perform the operation for $k=3$. That is, swap the values of $B_3$ and $B_4$, making $B = (2,1,4,3,5)$. * Perform the operation for $k=4$. That is, swap the values of $B_2$ and $B_3$, making $B = (2,4,1,3,5)$. After all the operations, we have $B_3=1$, so $S_2 = 3$. Similarly, we have the following. * For $i=1$: performing the operation for $k=2,3,4$ in this order makes $B=(1,4,3,2,5)$, so $S_1=1$. * For $i=3$: performing the operation for $k=1,2,4$ in this order makes $B=(2,1,3,4,5)$, so $S_3=2$. * For $i=4$: performing the operation for $k=1,2,3$ in this order makes $B=(2,3,4,1,5)$, so $S_4=4$.
3 3 2 2 2
1 1 1
10 10 1 1 1 9 4 4 2 1 3 3
2 2 2 3 3 3 1 3 4 4
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