Consider a two-dimensional coordinate plane, where the $x$\-axis is oriented to the right, and the $y$\-axis is oriented upward.
In this plane, there is a quadrilateral without self-intersection.
The coordinates of the four vertices are $(A_x,A_y)$, $(B_x,B_y)$, $(C_x,C_y)$, and $(D_x,D_y)$, in counter-clockwise order.
Determine whether this quadrilateral is convex.
Here, a quadrilateral is convex if and only if all four interior angles are less than $180$ degrees.
## Constraints
* $-100 \leq A_x,A_y,B_x,B_y,C_x,C_y,D_x,D_y \leq 100$
* All values in input are integers.
* The given four points are the four vertices of a quadrilateral in counter-clockwise order.
* The quadrilateral formed by the given four points has no self-intersection and is non-degenerate. That is,
* no two vertices are at the same coordinates;
* no three vertices are colinear; and
* no two edges that are not adjacent have a common point.
## Input
Input is given from Standard Input in the following format:
$A_x$ $A_y$
$B_x$ $B_y$
$C_x$ $C_y$
$D_x$ $D_y$
[samples]