2 3 7 9
4 * First, we will cut the log of length $7$ at a point whose distance from an end of the log is $3.5$, resulting in two logs of length $3.5$ each. * Next, we will cut the log of length $9$ at a point whose distance from an end of the log is $3$, resulting in two logs of length $3$ and $6$. * Lastly, we will cut the log of length $6$ at a point whose distance from an end of the log is $3.3$, resulting in two logs of length $3.3$ and $2.7$. In this case, the longest length of a log will be $3.5$, which is the shortest possible result. After rounding up to an integer, the output should be $4$.
3 0 3 4 5
5
10 10 158260522 877914575 602436426 24979445 861648772 623690081 433933447 476190629 262703497 211047202
292638192
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"content": "We have $N$ logs of lengths $A_1,A_2,\\cdots A_N$.\nWe can cut these logs at most $K$ times in total. When a log of length $L$ is cut at a point whose distance from an end of the log is $t$ $(0<t<L)$, i...",
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