5
3 5 7 11 31 Let us see if this output actually satisfies the conditions. First, $3$, $5$, $7$, $11$ and $31$ are all different, and all of them are prime numbers. The only way to choose five among them is to choose all of them, whose sum is $a_1+a_2+a_3+a_4+a_5=57$, which is a composite number. There are also other possible outputs, such as `2 3 5 7 13`, `11 13 17 19 31` and `7 11 5 31 3`.
6
2 3 5 7 11 13 * $2$, $3$, $5$, $7$, $11$, $13$ are all different prime numbers. * $2+3+5+7+11=28$ is a composite number. * $2+3+5+7+13=30$ is a composite number. * $2+3+5+11+13=34$ is a composite number. * $2+3+7+11+13=36$ is a composite number. * $2+5+7+11+13=38$ is a composite number. * $3+5+7+11+13=39$ is a composite number. Thus, the sequence `2 3 5 7 11 13` satisfies the conditions.
8
2 5 7 13 19 37 67 79
{
"problem": {
"name": "Five, Five Everywhere",
"description": {
"content": "Print a sequence $a_1, a_2, ..., a_N$ whose length is $N$ that satisfies the following conditions: * $a_i$ $(1 \\leq i \\leq N)$ is a prime number at most $55$ $555$. * The values of $a_1, a_2, ...",
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"memory_limit": 262144
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"sign": "abc096_d"
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"statements": [
{
"statement_type": "Markdown",
"content": "Print a sequence $a_1, a_2, ..., a_N$ whose length is $N$ that satisfies the following conditions:\n\n* $a_i$ $(1 \\leq i \\leq N)$ is a prime number at most $55$ $555$.\n* The values of $a_1, a_2, ......",
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