Olya wants to buy a custom wardrobe. It should have _n_ boxes with heights _a_1, _a_2, ..., _a__n_, stacked one on another in some order. In other words, we can represent each box as a vertical segment of length _a__i_, and all these segments should form a single segment from 0 to without any overlaps.
Some of the boxes are important (in this case _b__i_ = 1), others are not (then _b__i_ = 0). Olya defines the _convenience_ of the wardrobe as the number of important boxes such that their bottom edge is located between the heights _l_ and _r_, inclusive.
You are given information about heights of the boxes and their importance. Compute the maximum possible convenience of the wardrobe if you can reorder the boxes arbitrarily.
## Input
The first line contains three integers _n_, _l_ and _r_ (1 ≤ _n_ ≤ 10 000, 0 ≤ _l_ ≤ _r_ ≤ 10 000) — the number of boxes, the lowest and the highest heights for a bottom edge of an important box to be counted in convenience.
The second line contains _n_ integers _a_1, _a_2, ..., _a__n_ (1 ≤ _a__i_ ≤ 10 000) — the heights of the boxes. It is guaranteed that the sum of height of all boxes (i. e. the height of the wardrobe) does not exceed 10 000: Olya is not very tall and will not be able to reach any higher.
The second line contains _n_ integers _b_1, _b_2, ..., _b__n_ (0 ≤ _b__i_ ≤ 1), where _b__i_ equals 1 if the _i_\-th box is important, and 0 otherwise.
## Output
Print a single integer — the maximum possible convenience of the wardrobe.
[samples]
## Note
In the first example you can, for example, first put an unimportant box of height 2, then put an important boxes of sizes 1, 3 and 2, in this order, and then the remaining unimportant boxes. The convenience is equal to 2, because the bottom edges of important boxes of sizes 3 and 2 fall into the range \[3, 6\].
In the second example you have to put the short box under the tall box.