_Mathematician Pang_ learned Dirichlet convolution during the previous camp. However, compared with deep reinforcement learning, it's too easy for him. Therefore, he did something special.
If $f, g : {1, 2, \\dots, n} arrow.r ZZ$ are two functions from the positive integers to the integers, the Dirichlet convolution $f * g$ is a new function defined by: $$(f * g)(n) =\sum_{d \mid n}f(d)g ({\frac {n}{d}}) .$$
We define the $k$-th power of an function $g = f^k$ by $$ f^{k}=\underbrace {f * \dots * f} _{k~{\textrm {times}}}.$$
In this problem, we want to solve the inverse problem: Given $g$ and $k$, you need to find a function $f$ such that $g = f^k$.
Moreover, there is an additional constraint that $f (1)$ and $g (1)$ must equal to $1$. And all the arithmetic operations are done on $FF_p$ where $p = 998244353$, which means that in the Dirichlet convolution, $(f * g) (n) = (sum_(d mid n) f (d) g (frac(n, d))) bmod p$.
The first line contains two integers $n$ and $k med (2 <= n <= 10^5, 1 <= k < 998244353)$ .
The second line contains n integers $g (1), g (2),..., g (n)$ ($0 <= g (i) < 998244353, g (1) = 1$).
If there is no solution, output $-1$.
Otherwise, output $f (1), f (2),..., f (n)$ ($0 <= f (i) < 998244353, f (1) = 1$). If there are multiple solutions, print anyone.
## Input
The first line contains two integers $n$ and $k med (2 <= n <= 10^5, 1 <= k < 998244353)$ .The second line contains n integers $g (1), g (2),..., g (n)$ ($0 <= g (i) < 998244353, g (1) = 1$).
## Output
If there is no solution, output $-1$.Otherwise, output $f (1), f (2),..., f (n)$ ($0 <= f (i) < 998244353, f (1) = 1$). If there are multiple solutions, print anyone.
[samples]
**Definitions**
Let $ p = 998244353 $.
Let $ n, k \in \mathbb{Z} $ with $ 2 \leq n \leq 10^5 $, $ 1 \leq k < p $.
Let $ g: \{1, 2, \dots, n\} \to \mathbb{Z}/p\mathbb{Z} $ be a function with $ g(1) = 1 $.
Let $ f: \{1, 2, \dots, n\} \to \mathbb{Z}/p\mathbb{Z} $ be the unknown function with $ f(1) = 1 $, such that $ g = f^{*k} $, where $ f^{*k} $ denotes the $ k $-fold Dirichlet convolution of $ f $ with itself.
**Constraints**
1. $ g(i) \in \mathbb{Z}/p\mathbb{Z} $ for all $ i \in \{1, \dots, n\} $, and $ g(1) = 1 $.
2. $ f(1) = 1 $.
3. All operations are performed modulo $ p $.
4. For all $ m \in \{1, \dots, n\} $:
$$
g(m) = \sum_{d \mid m} f(d) \cdot f^{*(k-1)}\left(\frac{m}{d}\right) \mod p
$$
**Objective**
Find a function $ f $ satisfying $ f^{*k} = g $, or output $-1$ if no such $ f $ exists.