{"problem":{"name":"CTZ","description":{"content":"For a positive integer $X$, let $\\text{ctz}(X)$ be the (maximal) number of consecutive zeros at the **end** of the binary notation of $X$.   If the binary notation of $X$ ends with a $1$, then $\\text{","description_type":"Markdown"},"platform":"AtCoder","limit":{"time_limit":2000,"memory_limit":262144},"difficulty":"None","is_remote":true,"is_sync":true,"sync_url":null,"sign":"abc336_b"},"statements":[{"statement_type":"Markdown","content":"For a positive integer $X$, let $\\text{ctz}(X)$ be the (maximal) number of consecutive zeros at the **end** of the binary notation of $X$.  \nIf the binary notation of $X$ ends with a $1$, then $\\text{ctz}(X)=0$.\nYou are given a positive integer $N$. Print $\\text{ctz}(N)$.\n\n## Constraints\n\n*   $1\\leq N\\leq 10^9$\n*   $N$ is an integer.\n\n## Input\n\nThe input is given from Standard Input in the following format:\n\n$N$\n\n[samples]","is_translate":false,"language":"English"}],"meta":{"iden":"abc336_b","tags":[],"sample_group":[["2024","3\n\n$2024$ is `11111101000` in binary, with three consecutive `0`s from the end, so $\\text{ctz}(2024)=3$.  \nThus, print $3$."],["18","1\n\n$18$ is `10010` in binary, so $\\text{ctz}(18)=1$.  \nNote that we count the trailing zeros."],["5","0"]],"created_at":"2026-03-03 11:01:14"}}