{"problem":{"name":"Resistors in Parallel","description":{"content":"Given is a sequence of $N$ integers $A_1, \\ldots, A_N$. Find the (multiplicative) inverse of the sum of the inverses of these numbers, $\\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}$.","description_type":"Markdown"},"platform":"AtCoder","limit":{"time_limit":2000,"memory_limit":262144},"difficulty":"None","is_remote":true,"is_sync":true,"sync_url":null,"sign":"abc138_b"},"statements":[{"statement_type":"Markdown","content":"Given is a sequence of $N$ integers $A_1, \\ldots, A_N$.\nFind the (multiplicative) inverse of the sum of the inverses of these numbers, $\\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}$.\n\n## Constraints\n\n*   $1 \\leq N \\leq 100$\n*   $1 \\leq A_i \\leq 1000$\n\n## Input\n\nInput is given from Standard Input in the following format:\n\n$N$\n$A_1$ $A_2$ $\\ldots$ $A_N$\n\n[samples]","is_translate":false,"language":"English"}],"meta":{"iden":"abc138_b","tags":[],"sample_group":[["2\n10 30","7.5\n\n$\\frac{1}{\\frac{1}{10} + \\frac{1}{30}} = \\frac{1}{\\frac{4}{30}} = \\frac{30}{4} = 7.5$.\nPrinting `7.50001`, `7.49999`, and so on will also be accepted."],["3\n200 200 200","66.66666666666667\n\n$\\frac{1}{\\frac{1}{200} + \\frac{1}{200} + \\frac{1}{200}} = \\frac{1}{\\frac{3}{200}} = \\frac{200}{3} = 66.6666...$.\nPrinting `6.66666e+1` and so on will also be accepted."],["1\n1000","1000\n\n$\\frac{1}{\\frac{1}{1000}} = 1000$.\nPrinting `+1000.0` and so on will also be accepted."]],"created_at":"2026-03-03 11:01:13"}}